Siemka ; ] Proszę o Rozwiązanie równań kwadratowych ;) Zróbcie wszystko po koleij . Postać Iloczynowa X1 i X2 Miejsca zerowe .. a=,b=,c= Prosze to an jutro !!!!!! a)x²+6x+5=0 b)2x²-7x=0, c)-x²+9+=0 d)3x²-4x+7=0 e)-2x²+4x-2=0 f) 7x²+9=0 g)1/2x²-14x=0 h)5x²-25x+30=0 i)-x²-16=0 Opiszcie co wszystko co pokoleij !: }}}}}}
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a)x²+6x+5=0
a = 1
b = 6
c = 5
Δ = 6² - 4*5*1 = 36 - 20 = 16
√Δ = 4
x₁ = -6-4/2 = -5
x₂ = -6+4 / 2 = -1
b)2x²-7x=0
a = 2
b = -7
c = 0
Δ = (-7)² - 4*2*0 = 49
√Δ = 7
x₁ = 7-7/4 = 0
x₂ = 7+7/4 = 3,5
c)-x²+9=0
a = -1
b = 0
c = 9
Δ = 0² - 4*(-1)*9 = 36
√Δ = 6
x₁ = -6/-2 = 3
x₂ = 6/-2 = -3
d)3x²-4x+7=0
a = 3
b = -4
c = 7
Δ = (-4)²-7*3*4 = 16 - 84 = -68
-68 < 0
brak rozw.
e)-2x²+4x-2=0
a = -2
b = 4
c = -2
Δ=4²-(-2)*(-2)*4 = 16 - 16 = 0
x₁ = -4/-4 = 1
f) 7x²+9=0
a = 7
b = 0
c = 9
Δ = 0²-4*7*9 = -252
-252 < 0
brak rozw.
g)½x²-14x=0
a = ½
b = -14
c = 0
Δ = (-14)² - 4*½*0 = 196
√Δ = 14
x₁ = 14-14/2 = 0
x₂ = 14+14/2 = 14
h)5x²-25x+30=0
a = 5
b = -25
c = 30
Δ = (-25)² - 4*30*5 = 625 - 600 = 25
√Δ = 5
x₁ = 25-5/10 = 2
x₂ = 25+5/10=3
i)-x²-16=0
a = -1
b = 0
c = -16
Δ = -4*(-16)*(-1) = -64
-64 < 0
brak rozw.