Zad na poziomie liceum/technikum kl I.
Naszkicuj parabolę o podanym równaniu:
a) y= -1/2(x-1)²+3 ;
b) y= -4(x-4)²+1
Proooooszę, pomocy !!
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y=a(x-p)²+q
a>0 ramiona skierowane do gory
a<0 ramiona skierowane w dol
(p;q) wspolrzedne wierzcholka paraboli
a) y=-1/2(x-1)²+3
y=-1/2(x²-2x+1)+3
y=-1/2x²+x-1/2+3
y=-1/2x²+x+2,5
Δ=1-4·(-1/2)·2,5
Δ=1+5=6
x 1=(-1-√6)/(-1)≈3,45
x 2=(-1+√6)/(-1)≈-1,45
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