Question

Z matmy :4(x-2)-(x+2)(x+2)=1/2x +1-x do kwadratu

x(x-3)(x+1)-x do szescianu = 2-2x do kwadratu

2x(x+4)-(3x-1)(3x-1)=6-7(x do kwadratu -1)

2[(x-4)(x-4)-3(x+1)(x+1)+(4x-2)(4x-2)]-28x do kwadratu =19-27x

Answer 1

4(x-2)-(x+2)(x+2)=½x+1-x²

4x-8-x²-2x-2x-4=½x+1-x²

-x²+x²+4x-2x-2x-½x=1+4+8

-½x=13 /: (-½)

x=-26

 

 

x(x-3)(x+1)-x³=2-2x²

x(x²+x-3x-3)-x³=2-2x²

x³+x²-3x²-3x-x³=2-2x²

x³-x³+x²-3x²+2x²=2

0=2

 

2x(x+4)-(3x-1)(3x-1)=6-7(x²-1)

2x²+8x-9x²+3x+3x-1=6-7x²+7

2x²-9x²+7x²+8x+3x+3x=7+6+1

14x=14 /:14

x=1

 

2[(x-4)(x-4)-3(x+1)(x+1)+(4x-2)(4x-2)]-28x²=19-27x

2[x²-4x-4x+16-3(x²+x+x+1)+16x²-8x-8x+4]-28x²=19-27x

2[x²-4x-4x+16-3x²-3x-3x-3+16x²-8x-8x+4]-28x²=19-27x

2x²-8x-8x+32-6x²-6x-6x-6+32x²-16x-16x+8-28x²=19-27x

2x²-6x²+32x²-28x²-8x-8x-6x-6x-16x-16x+27x=19-8+6-32

-33x=-15 /: (-33)

x=¹⁵/₃₃