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Df --> 3x+6 ≥ 0
3x ≥ -6
x ≥ -2
Df={x|x ≥ -2, x∈ R}
b) f(x)=(x+1)/(2x-1)
Df---> 2x-1≠ 0
2x ≠ 1
x ≠1/2
Df = {x|x<1/2 atau x>1/2, x ∈R}