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Verified answer
U1= ar^n-1 = 64.½^1-1 = 64u2= ar^n-1 = 64.½^2-1 = 32
u3= ar^n-1 = 64.½^3-1 = 64.¼ = 16
u4= ar^n-1 = 64.½^4-1 = 64. ⅛ = 8
Verified answer
Mapel MatematikaBab Baris dan Deret
Barisan Geometri
a = 64
r = 1/2
U1 = a = 64
U2 = ar = 64(1/2) = 32
U3 = ar^2 = 64(1/2)^2 = 16
U4 = ar^3 = 64(1/2)^3 = 8
Maka empat suku pertama barisan geometri tsb adalah 64, 32, 16, 8