Zad1
Zapisz w postaci potęgi
a) (2/b) *(a/b)*(a/b)*(a/b)
b) x*x*x*x / y*y*y*y
c) 1/ x*x*x
zad2.
Oblicz
a) 2⁴, (1.2)² , (2 1/3)³ , (4 7/9)⁰ b) (1/4)⁻³ , (0,15)⁻¹ , (-3 1/5)⁻², (-1/2)⁻⁵
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a) (a/b) *(a/b)*(a/b)*(a/b)= (a/b)^4
b) x*x*x*x / y*y*y*y = (x/y)^4
c) 1/ x*x*x = x^-3
a) 2⁴ = 16
(1.2)² = 1,44
(2 1/3)³= (7/3)^3 = 343/27 = 12 19/27
(4 7/9)⁰ = 1
b) (1/4)⁻³ = 4^3 = 64
(0,15)⁻¹ = 100/15 = 20/3 = 6 2/3
(-3 1/5)⁻² = (-16/5)^-2 = (-5/16)^2 = 25/256
(-1/2)⁻⁵ = (-2)^5 = -32
a) (2/b) *(a/b)*(a/b)*(a/b)= (2/b)*3^(a/b)
b) x*x*x*x / y*y*y*y=4^x / 4^y razy
c) 1/ x*x*x= 1/ 3^x
zad2.
Oblicz
a) 2⁴=2*2*2*2=16, (1.2)²=1,2*1,2=1,44 , (2 1/3)³=7^3=343, (4 7/9)⁰=1bo każda liczba podniesiona do potęgi 0 wynosi 1 b) (1/4)⁻³=4^3=64 , (0,15)⁻¹=100/15^1=100/15 , (-3 1/5)⁻²=-5/31^2=25/961, (-1/2)⁻⁵= -2^5=-32
^ podniesione do potęgi np. 2^3..dwa do potęgi 3
/ kreska ułamkowa
myśle że pomogłam licez na naj.