Question

Zad1

Zapisz w postaci potęgi

a) (2/b) *(a/b)*(a/b)*(a/b)

b) x*x*x*x / y*y*y*y

c) 1/ x*x*x

zad2.

Oblicz

a) 2⁴, (1.2)² , (2 1/3)³ , (4 7/9)⁰ b) (1/4)⁻³ , (0,15)⁻¹ , (-3 1/5)⁻², (-1/2)⁻⁵

Prosze na dzisiaj

Dam Najj

Answer 1

a) (a/b) *(a/b)*(a/b)*(a/b)= (a/b)^4

b) x*x*x*x / y*y*y*y = (x/y)^4

c) 1/ x*x*x = x^-3

 

a) 2⁴ = 16

 (1.2)² = 1,44

(2 1/3)³= (7/3)^3 = 343/27 = 12 19/27

 (4 7/9)⁰ = 1

 

b) (1/4)⁻³ = 4^3 = 64

(0,15)⁻¹ = 100/15 = 20/3 = 6 2/3

(-3 1/5)⁻² = (-16/5)^-2 = (-5/16)^2 = 25/256

(-1/2)⁻⁵ = (-2)^5 = -32

 

Answer 2

a) (2/b) *(a/b)*(a/b)*(a/b)= (2/b)*3^(a/b)

b) x*x*x*x / y*y*y*y=4^x / 4^y razy 

c) 1/ x*x*x= 1/ 3^x

 

zad2.

Oblicz

 

a) 2⁴=2*2*2*2=16, (1.2)²=1,2*1,2=1,44 , (2 1/3)³=7^3=343, (4 7/9)⁰=1bo każda liczba podniesiona do potęgi 0 wynosi 1       b) (1/4)⁻³=4^3=64 , (0,15)⁻¹=100/15^1=100/15 , (-3 1/5)⁻²=-5/31^2=25/961, (-1/2)⁻⁵= -2^5=-32

 

^ podniesione do potęgi np. 2^3..dwa do potęgi 3 

/ kreska ułamkowa 

myśle że pomogłam licez na naj.