2per x²+3x+2 ditambah 3per x+1 =.... Question from @Nurfinasari

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September 2018 2 35 Report

2per x²+3x+2 ditambah 3per x+1 =

Takamori37 $$\begin{align}\frac{2}{x^2+3x+2}+\frac{3}{x+1}&=\frac{2}{(x+1)(x+2)}+\frac{3}{x+1} \\ &=\frac{2+3(x+2)}{(x+1)(x+2)} \\ &=\frac{2+3x+6}{x^2+3x+2} \\ &=\frac{3x+8}{x^2+3x+2}\end{align}$

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sriguanti10 (2/x^2+3x+2)+(3/x+1)={2(x+1)+3(x^2+3x+2)}/{x^2+3x+2+x+1}
={2x+2+3x^2+9x+6}/{x^2+4x+3}
={11x+8+3x^2}/{x^2+4x+3}
={(3x+8)(x+1)}/{(x+3)(x+1)}
=(3x+8)/(x+3)

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