Nilai yang memenuhi pertidaksamaan 3 akar 1/8 pangkat 2x > 64 pangkat 3x / 2pangkat 18x-36 adalah....
a. x<-14
b. x<-15
c. x<-16
d. x<-17
e. x<-18
a. x<-14
b. x<-15
c. x<-16
d. x<-17
e. x<-18
Takamori37
![$\begin{align}\sqrt[3]{\frac1{8^{2x}}}&\ \textgreater \ \frac{64^{3x}}{2^{18x-36}} \\ \sqrt[3]{(2^{-3})^{2x}}&\ \textgreater \ \frac{(2^6)^{3x}}{2^{18x-36}} \\ (2^{-6x})^{\textstyle\frac13}&\ \textgreater \ 2^{18x-(18x-36)} \\ 2^{-2x}&\ \textgreater \ 2^{36} \\ -2x&\ \textgreater \ 36~~~~\text{| Karena basis $\ \textgreater \ 1$, tanda tetap} \\ x&\ \textless \ -18\ \ [E] \end{align}](https://tex.z-dn.net/?f=%24%5Cbegin%7Balign%7D%5Csqrt%5B3%5D%7B%5Cfrac1%7B8%5E%7B2x%7D%7D%7D%26%5C+%5Ctextgreater+%5C+%5Cfrac%7B64%5E%7B3x%7D%7D%7B2%5E%7B18x-36%7D%7D+%5C%5C+%5Csqrt%5B3%5D%7B%282%5E%7B-3%7D%29%5E%7B2x%7D%7D%26%5C+%5Ctextgreater+%5C+%5Cfrac%7B%282%5E6%29%5E%7B3x%7D%7D%7B2%5E%7B18x-36%7D%7D+%5C%5C+%282%5E%7B-6x%7D%29%5E%7B%5Ctextstyle%5Cfrac13%7D%26%5C+%5Ctextgreater+%5C+2%5E%7B18x-%2818x-36%29%7D+%5C%5C+2%5E%7B-2x%7D%26%5C+%5Ctextgreater+%5C+2%5E%7B36%7D+%5C%5C+-2x%26%5C+%5Ctextgreater+%5C+36%7E%7E%7E%7E%5Ctext%7B%7C+Karena+basis+%24%5C+%5Ctextgreater+%5C++1%24%2C+tanda+tetap%7D+%5C%5C+x%26%5C+%5Ctextless+%5C+-18%5C+%5C+%5BE%5D+%5Cend%7Balign%7D "$\begin{align}\sqrt[3]{\frac1{8^{2x}}}&\ \textgreater \ \frac{64^{3x}}{2^{18x-36}} \\ \sqrt[3]{(2^{-3})^{2x}}&\ \textgreater \ \frac{(2^6)^{3x}}{2^{18x-36}} \\ (2^{-6x})^{\textstyle\frac13}&\ \textgreater \ 2^{18x-(18x-36)} \\ 2^{-2x}&\ \textgreater \ 2^{36} \\ -2x&\ \textgreater \ 36~~~~\text{| Karena basis $\ \textgreater \ 1$, tanda tetap} \\ x&\ \textless \ -18\ \ [E] \end{align}")
18 votes
Thanks 28
RobichMumtazy
Kalo diganti pernya jadi 3^18x-36?
Dillamchtr18
kog gkada?
ZydargeBKun
kok diganti sih?