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1)a=3 i b=6
zpitagorasa
3²+6²=c²
9+36=c²
45=c²
c=√45=3√5 ---->dl,przeciwprostokatnej
2)1 bok=a
2 bok b=2a
O=24
O=2a+2b
czyli :
24=2·a+2·2a
24=2a+4a
24=6a /;6
a=4 to b=2·4=8
Pole prostokata P=ab=4·8=32 m²
3)O=24
O=4a
4a=24 /:4
a=6
pole kwadratu P=a²=6²=36m²