oblicz iloczyn pierwszych 5 wyrazów ciągu geometrycnego danego wzorem
an=8/2^n, gdzie n (wieksze lub równe) 1.
z góry serdecznie dziękuje
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Zadanie w załączniku :)
an =8/2^n ;
a1 =8/2 =4
a2 =8/2^2 =8/4 =2
q =a2/a1 =2/4
q =1/2
---------
a3 =a2 *q =2 *1/2 =1
a4 =1 *1/2 =1/2
a5 =1/2 *1/2 =1/4
a1*a2*a3*a4*a5 =4*2*1*1/2 *1/4 =8/8 =1