Question

Rozwiaz a)x²-x=6
b)x-2/4-x+1/2>5

Answer 1

X²-x=6
x²-x-6=0
Δ=(-1)²-4*1*(-6)
Δ=1+24
Δ=25
√Δ=√25=5
x1=(1-5)/(2*1)
x1=-4/2
x1=-2
x2=(1+5)/(2*1)
x2=6/2
x2=3
x∈{-2,3}

(x-2)/4-(x+1)/2>5
(x-2)/4-(x+1)/2-5>0
2(x-2)-1*4(x+1)-5*2*4>0
-2x-40-8>0
-2x-48>0
2*4(-2x-48)>0
-2x-48>0
-2x>48 //:(-2)
x<-24
x∈(-∞,24)

Answer 2

A
x^2-x-6=0
delta= b^2-4ac=1-4*(-6)=25
x1= -b-√delta / 2a=1-5/2= -2
x2= -b+√delta /2a= 1+5/2=3
x1= - 2        x2=3
b
x-2/4-x + 1/2 >5
zakladam ze nierownosc wyglada tak
(x-4) / 4 - (x+1) / 2 >5  /*4
x-4 - 2*(x+1)>20
x-4-2x-2>20
-x > 26 ?*(-1)
x<-26
x nalezy(-nieskonczonosc ; -26)