Tentukan penyelesaian persamaan 0° ≤ x ≤ 360° a.sin x = 1/2 √3 b.cos 2x = - 1/2 c.tan x = 1
kekkaiisshi
Sin x = 1/2√3 sin x = sin 60 x = 60 + k.360 k = 0 ==> x = 60 atau x = (180 - 60) + k.360 x = 120 + k.360 k = 0 ==> x = 120 Hp = {60, 120}
cos 2x = cos 2x = cos 120 2x = 120 + k.360 x = 60 + k.180 k = 0 ==> x = 60 k = 1 ==> x = 240 atau 2x = -120 + k.360 x = -60 + k.180 k = 0 == > x = -60 (tdk memenuhi) k = 1 ==> x = 120 k = 2 ==> x = 300 Hp = {60, 120, 240, 300}
yang terajhir kerjakan sendiri ... semoga membantu :)
sin x = sin 60
x = 60 + k.360
k = 0 ==> x = 60
atau
x = (180 - 60) + k.360
x = 120 + k.360
k = 0 ==> x = 120
Hp = {60, 120}
cos 2x =
cos 2x = cos 120
2x = 120 + k.360
x = 60 + k.180
k = 0 ==> x = 60
k = 1 ==> x = 240
atau
2x = -120 + k.360
x = -60 + k.180
k = 0 == > x = -60 (tdk memenuhi)
k = 1 ==> x = 120
k = 2 ==> x = 300
Hp = {60, 120, 240, 300}
yang terajhir kerjakan sendiri ... semoga membantu :)