Question

6/5-37/3÷(4 1/3-2/5+1)+1/10

El cautro qu esta adentro del parentesis significa que es un número mixto.

(1/3-2/5)÷2/5+2/3-(3/4+15/2×1/20)

(1/5-3/4)÷22/5-(5/2+7/10×5/4)+5/4

-19/15÷(-38/3)+2×7/30-(5/12-1)

(3/5-1)÷5/6+5/6-(7/10+18/21×14/20)

-32/5×3/16-(-2+4/3)÷(-1/9+1/3)

7/6 (9/10+18/21÷20/14)+(3/5-1)×3/2




CONFIO EN VOS Sabius95​

Answer 1

Verified answer

PROCEDIMIENTOS:

[tex]\frac{6}{5}-\frac{37}{3}\div \left(\frac{41}{3}-\frac{2}{5}+1\right)+\frac{1}{10}=\frac{6}{5}-\frac{37}{3}\div \frac{214}{15}+\frac{1}{10}=\frac{6}{5}-\frac{185}{214}+\frac{1}{10}=\frac{233}{535}[/tex]

Resultado: [tex]\frac{233}{535}[/tex]

[tex]\left(\frac{1}{3}-\frac{2}{5}\right)\div \frac{2}{5}+\frac{2}{3}-\left(\frac{3}{4}+\frac{15}{2}*\:\frac{1}{20}\right) =\\\\-\frac{1}{3} *\frac{5}{2} +\frac{2}{3} -(\frac{3}{4} +\frac{3}{2}*\frac{1}{4} )=\\\\\-\frac{5}{6} +\frac{2}{3} -(\frac{3}{4} +\frac{3}{8} )=-\frac{5}{6} +\frac{2}{3} -\frac{9}{8} =-\frac{31}{24}[/tex]

Resultado: [tex]-\frac{31}{24}[/tex]

[tex]\left(\frac{1}{5}-\frac{3}{4}\right)\div \frac{22}{5}-\left(\frac{5}{2}+\frac{7}{10}\times \frac{5}{4}\right)+\frac{5}{4}=\\\\-\frac{11}{20}\div \frac{22}{5}-\left(\frac{5}{2}+\frac{7}{10}\times \frac{5}{4}\right)+\frac{5}{4}=\\\\-\frac{11}{20}\div \frac{22}{5}-\frac{27}{8}+\frac{5}{4}=-\frac{1}{8}-\frac{27}{8}+\frac{5}{4}=-\frac{9}{4}[/tex]

Resultado: [tex]-\frac{9}{4}[/tex]

[tex]-\frac{19}{15}\div \left(-\frac{38}{3}\right)+2*\:\frac{7}{30}-\left(\frac{5}{12}-1\right)\\\\\frac{19}{15} *\frac{3}{38} +\frac{7}{15} -(-\frac{7}{12} )\\\\\frac{1}{5} *\frac{1}{2} +\frac{7}{15} +\frac{7}{12} =\\\\\frac{1}{10} +\frac{7}{15} +\frac{7}{12} =\frac{23}{20}[/tex]

Resultado: [tex]\frac{23}{20}[/tex]

[tex]\left(\frac{3}{5}-1\right)\div \frac{5}{6}+\frac{5}{6}-\left(\frac{7}{10}+\frac{18}{21}\cdot \frac{14}{20}\right)=\\\\\left(\frac{3}{5}-1\right)\div \frac{5}{6}+\frac{5}{6}-\left(\frac{7}{10}+\frac{6}{7}\cdot \frac{14}{20}\right)=\\\\\left(\frac{3}{5}-1\right)\div \frac{5}{6}+\frac{5}{6}-\left(\frac{7}{10}+\frac{6}{7}\cdot \frac{7}{10}\right) =\\\\-\frac{2}{5}\div \frac{5}{6}+\frac{5}{6}-\left(\frac{7}{10}+\frac{6}{7}\cdot \frac{7}{10}\right)=\\\\-\frac{2}{5}\div \frac{5}{6}+\frac{5}{6}-\frac{13}{10}=[/tex]

[tex]-\frac{12}{25}+\frac{5}{6}-\frac{13}{10} =-\frac{71}{75}[/tex]

Resultado: [tex]-\frac{71}{75}[/tex]

[tex]-\frac{32}{5}*\:\frac{3}{16}-\left(-2+\frac{4}{3}\right)\div \left(-\frac{1}{9}+\frac{1}{3}\right)=\\\\-\frac{2}{5} *3-(-\frac{2}{3} )\div \frac{2}{9} \\\\-\frac{6}{5} +\frac{2}{3} *\frac{9}{2} \\\\-\frac{6}{5} +3=\frac{9}{5}[/tex]

Resultado: [tex]\frac{9}{5}[/tex]

[tex]\frac{7}{6}\left(\frac{9}{10}+\frac{18}{21}\div \frac{20}{14}\right)+\left(\frac{3}{5}-1\right)*\:\frac{3}{2}\\\\\frac{7}{6} *(\frac{9}{10} +\frac{14}{20} )-\frac{2}{5} *\frac{3}{2} \\\\\frac{7}{6} *(\frac{9}{10} +\frac{6}{7} *\frac{7}{10} )-\frac{1}{5} *3\\\\\frac{7}{6} *(\frac{9}{10} +3*\frac{1}{5} )-\frac{3}{5} \\\\\frac{7}{6} *\frac{3}{2} -\frac{3}{5} \\\\\frac{7}{2} *\frac{1}{2} -\frac{3}{5} =\frac{7}{4} -\frac{3}{5} =\frac{23}{20}[/tex]

Resultado: [tex]\frac{23}{20}[/tex]

Atte: Sabius95