2.a. Jika f(x) = ax+b,f(1) = 2, dan f(2)=1. Maka tentukan Bentuk fungsi f(x) 3. Diketahui f(x) = ax+b. Tentukan bentuk fungsi² berikut jika A. F(1) = 3 dan f(2) = 5 B. F(0) = -6 dan f(3) = -5 C. F(2) = 3 dan f(4) = 4.
Galladeaviero
A. f(2) = 1 f(1) = 2 (2-1) a = 1- 2 a = -1 dan b = 1 - 2a --> b = 1+2 = 3 f(x) = ax+b --> f(x) = -x + 3 atau f(x) = 3 - x . 3) a) f(2) - f(1) = 5-3 (2-1)a = 2 a = 2 --> b = 3 - a --> b = 1 f(x) = 2x +1 . b) f(3) - f(0) = -5 -(-6) = 1 (3-0) a = 1 a= 1/3 dan b = -5 - 3a = -5-3(1/3) = -5 -1 = -6 f(x) = 1/3x - 6 . c) f(4) - f(2) = 4-3 (4-2) a = 1 2a = 1 a = 1/2 dan b = 3 - 2a --> b = 3-2(1/2) = 2 f(x) = 1/2 x + 2
f(1) = 2
(2-1) a = 1- 2
a = -1 dan b = 1 - 2a --> b = 1+2 = 3
f(x) = ax+b --> f(x) = -x + 3 atau f(x) = 3 - x
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3)
a) f(2) - f(1) = 5-3
(2-1)a = 2
a = 2 --> b = 3 - a --> b = 1
f(x) = 2x +1
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b) f(3) - f(0) = -5 -(-6) = 1
(3-0) a = 1
a= 1/3 dan b = -5 - 3a = -5-3(1/3) = -5 -1 = -6
f(x) = 1/3x - 6
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c)
f(4) - f(2) = 4-3
(4-2) a = 1
2a = 1
a = 1/2 dan b = 3 - 2a --> b = 3-2(1/2) = 2
f(x) = 1/2 x + 2