Dane są dwa wektory : a=[3,-1] oraz b=[5,3] . Znajdź takie wektory x , aby : a) 2*x+3*a=b b) 1/3*x+b=2a c) x=3*a-1/2b d) 1/2*b=-1/2a-2*x e) 3*(x-a)=2*(x+b)
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A) 2x=b-3a /:2 x=1/2b-3/2a x=1/2*[3,-1]-3/2*[5,3]=[3/2,-1/2]-[15/2,9/2]=[-6,-5] b) 1/3x+b=2a /*3 x=6a-3b x=6*[3,-1]-3*[5,3]=[18,-6]-[15,9]=[3,-15] c) x=3a-1/2b=3*[3,-1]-1/2*[5,3]=[9,-3]-[5/2,3/2]=[13/2, -9/2] d) 2x=-1/2a-1/2b /:2 x=-1/4a-1/4b x=-1/4*[3,-1]-1/4*[5,3]=[-3/4,1/4]-[5/4,3/4]=[-2,-1/2] e) 3x-3a=2x+2b 3x-2x=3a+2b x=3a+2b x=3*[3,-1]+2*[5,3]=[9,-3]+[10,6]=[19,3]
2x=b-3a /:2
x=1/2b-3/2a
x=1/2*[3,-1]-3/2*[5,3]=[3/2,-1/2]-[15/2,9/2]=[-6,-5]
b)
1/3x+b=2a /*3
x=6a-3b
x=6*[3,-1]-3*[5,3]=[18,-6]-[15,9]=[3,-15]
c)
x=3a-1/2b=3*[3,-1]-1/2*[5,3]=[9,-3]-[5/2,3/2]=[13/2, -9/2]
d)
2x=-1/2a-1/2b /:2
x=-1/4a-1/4b
x=-1/4*[3,-1]-1/4*[5,3]=[-3/4,1/4]-[5/4,3/4]=[-2,-1/2]
e)
3x-3a=2x+2b
3x-2x=3a+2b
x=3a+2b
x=3*[3,-1]+2*[5,3]=[9,-3]+[10,6]=[19,3]