błagaam.. rozwiążcie mi to: ((√72+√20)⋅(√18-√5))/2
((6√2+2√5)·(3√2-√5))/2=(36-6√10+6√10-10)/2=26/2=13
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((6√2+2√5)·(3√2-√5))/2=(36-6√10+6√10-10)/2=26/2=13