Question

13.Oblicz:
a. √25/36
b.√2¼
c.³√2 10/27
d.√40½:√8
e. ³√4 : ³√2
f. ³√-27: ³√8

Answer 1

[tex]a)\ \ \sqrt{\frac{25}{36}}=\frac{\sqrt{25}}{\sqrt{36}}=\frac{5}{6}\\\\\\b)\ \ \sqrt{2\frac{1}{4}}=\sqrt{\frac{9}{4}}=\frac{\sqrt{9}}{\sqrt{4}}=\frac{3}{2}=1\frac{1}{2}\\\\\\c)\ \ \sqrt[3]{2\frac{10}{27}}=\sqrt[3]{\frac{64}{27}}=\frac{\sqrt[3]{64}}{\sqrt[3]{27}}=\frac{4}{3}=1\frac{1}{3}\\\\\\d)\ \ \sqrt{40\frac{1}{2}}:\sqrt{8}=\sqrt{40\frac{1}{2}:8}=\sqrt{\frac{81}{2}\cdot\frac{1}{8}}=\sqrt{\frac{81}{16}}=\frac{\sqrt{81}}{\sqrt{16}}=\frac{9}{4}=2\frac{1}{4}[/tex]

[tex]e)\ \ \sqrt[3]{4}:\sqrt[3]{2}=\sqrt[3]{4:2}=\sqrt[3]{2}\\\\\\f)\ \ \sqrt[3]{-27}:\sqrt[3]{8}=-3:2=-\frac{3}{2}=-1\frac{1}{2}[/tex]