Jawab:[tex]\rm \displaystyle x=\frac{3-2log_2(5)}{4}[/tex]
Penjelasan :[tex]\displaystyle2^{4x-3}=\frac{1}{25}\\\\2^{4x-3}=\frac{1}{5^2}\\\\\because\frac{1}{n^a}=n^{-a}\therefore\\\\2^{4x-3}=5^{-2}\\\\a^b=c\:\:\rightarrow\:\:b=log_ac\\\\4x-3=log_2(5^{-2})\\\\\because log_a(b^c)=clog_ab\therefore\\\\4x-3=-2log_2(5)\\\\4x=3-2log_2(5)\\\\x=\frac{3-2log_2(5)}{4}[/tex]
(xcvi)
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Jawab:
[tex]\rm \displaystyle x=\frac{3-2log_2(5)}{4}[/tex]
Penjelasan :
[tex]\displaystyle2^{4x-3}=\frac{1}{25}\\\\2^{4x-3}=\frac{1}{5^2}\\\\\because\frac{1}{n^a}=n^{-a}\therefore\\\\2^{4x-3}=5^{-2}\\\\a^b=c\:\:\rightarrow\:\:b=log_ac\\\\4x-3=log_2(5^{-2})\\\\\because log_a(b^c)=clog_ab\therefore\\\\4x-3=-2log_2(5)\\\\4x=3-2log_2(5)\\\\x=\frac{3-2log_2(5)}{4}[/tex]
(xcvi)