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a = 1
b = √3/2
c² = a² + b² = 1 +(√3/2)² = 1 + 3/4 = 7/4
c =√(7/4) = √7/2
sin α = a/c = 1/(√7/2) = 2/√7 = [2√7]/7
sin β = b/c =[√3/2]/[√7/2] = [√3/2]*[2/√7] = √3/√7 =√(3/7)
b=√3/2
c²=1²+(√3/2)²
c²=1+¾=⁷/₄
c=√7/2
sinα=1:√7/2=²/₇√7
sinβ=√3/2:√7/2=√21/7
1+3/2 = c2
c= 1 i 3/2 - przeciwprostokatna
1: 1 i 3/2 =2/5 - sin jednego kata
√3/2 : 1 i 3/2 = 2/5 √3/2 - sin drugiego kata
;D