Question

carilah dy/dx jika y = sec (3x^5 + 6 )^ 1/2

Answer 1

[15x⁴/(2 (3x^5 +6)½)] tan(3x^5 +6)½sec (3x^5 +6)½. semoga membantu. jadikan yg terbaik yaa

Answer 2

Y = 1/cos√(3x^5 + 6)
pakai turunan u/v
y' = (u'v - uv')/v²

maka:
y' = (0 - 1(-sin (3x^5 + 6)^(-1/2) (15x^4))/(cos√(3x^5 + 6))²
= 15x^4/(√sin(3x^5 + 6)) (cos²√(3x^5 + 6)