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Verified answer
RACL = 1/(25π²) H
C = 25×10⁻⁶ F
fᵣ = ___?
frekuensi resonansi
fᵣ = 1/2π √(1 / (L C))
fᵣ = 1/2π √(1 / (1/(25π²) • 25×10⁻⁶))
fᵣ = 1/2π √(π² 10⁶)
fᵣ = 1/2π • π 10³
fᵣ = 500 Hz = 0,5 kHz ✔️