Question

bantuiin donkk sok 25 cm
sn 25 cm
fok2,5 fob 1/2cm
d 23

sok: 1/fok= 1/sok+ 1/sok

1/25=1/2,5+1/25 lanjutanya gmnn

Answer 1

A. BILA MATA BERAKOMODASI MAKSIMUM
1/f=1/sok+1/sok'
1/2,5=1/sok+1/25
1/2,5-1/25=1/sok
10/25-1/25=1/sok
9/25=1/sok
sok=25/9

d=sok+sob'
23=25/9 +sob'
sob'=23-25/9
sob'=207/9-25/9
sob'=182/9

1/fob=1/sob+1/sob'
1/(1/2)=1/sob+1(182/9)
2=1/sob+9/182
1/sob=2  -   9/182
1/sob=364/182 - 9/182
1/sob=355/182
sob=355/182

perbesaran
M=[sob'/sob] x [sn/fok  + 1]
M=[(182/9)/(355/182)] x [(25/2,5)+1]
M=114



B.BILA MATA TAK BERAKOMODASI

1/f=1/sok+1/sok'
1/2,5=1/sok+1/~
1/2,5=1/sok+0
1/2,5=1/sok
sok=2,5

d=sok+sob'
23=2,5 +sob'
sob'=23-2,5
sob'=20,5

1/fob=1/sob+1/sob'
1/(0,5)=1/sob+1/(20,5)
1/sob=2  -  1/20,5
1/sob=41/20,5-1/20,5
1/sob=40/20,5
sob=20,5/40
sob=0,5125

perbesaran
M=[sob'/sob] x [sn/fok]
M=[20,5/0,5125)] x [(25/2,5)+1]
M=40 x (10+1)
M=40x(11)
M=440