November 2018 1 4 Report

sinα=0,25

P=8

O=24

2a+2b=24 /:2

a+b=12

a=12-b

P=ab·sinα

8=(12-b)·b ·0,25

8=3b-0,25b²

3b-0,25b²-8=0 /·4

12b-b²-32=0

Δ=12²-4·(-1)·(-32)=16

√Δ=√16=4

b1=-12-4/ -2 =-16/-2=8

b2=-12+4/ -2 =-8/-2=4

skąd się bierze 8=3b-0,25b² i dalej ? ;c


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