Suatu suku banyak f(x) dibagi (x - 2) sisanya 5 dan (x + 2) adalah faktor dari f(x). jika f(x) dibagi x^2 - 4, sisanya adalah. . . a. 5x - 10 b. 5/4x + 5/2 c. 5x + 10 d. -5x + 30 e. -5/4x + 7/2
DB45 jawab B x- 2 = 0 --> x = 2 ---> f(2) = 5 x+2 = 0 --> x = - 2--> f(-2)= 0 (sisa nol krn faktor)
sisa jika x² - 4 --> s(x)= ax + b x² - 4 = 0 --> x = 2 atau x = - 2
s(2-) = f (-2) --> -2a + b =0 s(2) = f(2) --> 2a + b = 5 -4a = -5--> a = 5/4 b = 2a = 5/2
jawab B
x- 2 = 0 --> x = 2 ---> f(2) = 5
x+2 = 0 --> x = - 2--> f(-2)= 0 (sisa nol krn faktor)
sisa jika x² - 4 --> s(x)= ax + b
x² - 4 = 0 --> x = 2 atau x = - 2
s(2-) = f (-2) --> -2a + b =0
s(2) = f(2) --> 2a + b = 5
-4a = -5--> a = 5/4
b = 2a = 5/2
S(x)= 5/4 x + 5/2
atau
s(x) = 1/4 (5x + 10)