Question

Oblicz

([81^0,5]*{9^1/2})^-1/4

usuń niewymierność z pierwiastka

(√2-√3)/(√2+√3)

Answer 1

(√2-√3)/(√2+√3)=(√2-√3)(√2-√3)/(√2+√3)(√2-√3)=5-2√6/-1=-(5-2√6)=-5+2√6

 

(√2-√3)(√2-√3)=√2²-2√2√3+√3²=2-2√6+3=5-2√6

(√2+√3)(√2-√3)=√2²-√3²=2-3=-1

 

([81^0,5]*{9^1/2})^-1/4={(9²)^½*(3²)½)^-¼=(9*3)^-¼=⁴√1/⁴√27