Question

(√2+√3)÷√5

(1+2√2)÷√3

(2√3+3√2)÷ √6

(√3+√5 )÷ √3

(√12)÷ √75

Answer 1

jesli tu chodzi o usuniecie niewymiernosci z mianownika :

 

(pier2 + pir 3) / pier5 * pier5/pier5 = pier5(pier2 + pier3) /5 = (pier10 + pier15) /5 

 

(1 + 2pier2) / pier3 * pier3/pier3 = (pier3 + 2pier6) / 3

 

(2pier3 + 3pier2)  / pier6  * pier6 / pier6 = (2pier18 + 3pier12) / 6 = (6pier2 + 6pier3) /6 = 6(pier2 + pier3) /6 = pier2 + pier3

 

(pier3 + pier5) / pier3 * pier3/pier3 = pier3(pier3 + pier5) / 3 = (3 + pier15) / 3

 

pier12 / pier75 = pier(4 * 3) / pier(25 * 3) = 2pier3 / 5pier3 = 2/5

Answer 2

(√2+√3)÷√5=(1,41+1,73)/2,23=3,12/2,23=1,399

(1+2√2)÷√3=(1+2,82)/1,73=3,82/1,73=2,20

(2√3+3√2)÷ √6=(3,46+4,24)/2,44=5,7/2,44=2,33

(√3+√5 )÷ √3=(1,73+2,23)/1,73=3,96/1,73=2,29

(√12)÷ √75 =3,46/8,66=0,399