układ równań
prosze o rozwiązanie
3/5x+1/2y=2
1/2(2x-y)=2
x=2,5
y=1
i to ma być obiczone równaniem
{³/₅x+½y=2 / ·10
{½(2x-y)=2
{6x+5y=20
{x-½y=2
{x=½y+2
{6(½y+2)+5y=20
{3y+12+5y=20
{8y=20-12
8y=8 /:8
{x=½x+2
{y=1
{x=½·1+2=2½
{x=2½=2,5
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
{³/₅x+½y=2 / ·10
{½(2x-y)=2
{6x+5y=20
{x-½y=2
{6x+5y=20
{x=½y+2
{6(½y+2)+5y=20
{x=½y+2
{3y+12+5y=20
{x=½y+2
{8y=20-12
{x=½y+2
8y=8 /:8
{x=½x+2
{y=1
{x=½·1+2=2½
{y=1
{x=2½=2,5