Question

usun niewymierność z mianownika

(1+3√2)/(2√3)=

(4√2)/(4+√3)=

11/(5+√3)=

3/(√2+2)=

Answer 1

1+3√2 / 2√3 = 1+3√2 / 2√3 * 2√3 / 2√3= (1+3√2 ) * 2√3 / 2√3 *2√3 = 2√3 + 6√6 / 4*3 = 2√3 + 6√6 / 12 = √3 +3√6 / 5   ( 4√2) / ( 4+√3) = (4√2) / ( 4+√3) * (4-√3) / (4-√3) = 4√2 * (4-√3) / (4+√3) * (4-√3) = 16√2 - 4√3 / 16 + 4√3 - 4√3 - 3 = 16√2 - 4√3 / 13    11/ ( 5 + √3) = 11/ (5+ √3) * (5-√3)/(5-√3) = 11 * ( 5-√3) / (5+√3)*( 5- √3) = 55- 11√3 / 25 +5√3 - 5√3 - 3 = 55-11√3 / 22 = 5 - √3/ 2    3/(√2+2) = 3/ (√2+2) * (√2-2)/ (√2-2) = 3 * ( √2-2) / (√2+2) * (√2 -2) = 3√2 - 6 / 2- 2√22 +2√2 - 4 = 3√2 - 6 /  -2 = -3√2 +6 / 2  nie jestem pewna czy jest dobrze na 100 % ale na 90 % raczej tak :)