Question

2:(2 do potęgi minus 2 plus 4 do potęgi minus jedna druga) do minus 1

Answer 1

2:(2⁻² + 4⁻¹/²)⁻¹ = 2:[(½)² +(¼)¹/²]⁻¹ = 2:[¼+√(¼)]⁻¹ = 2:(¼+½)⁻¹ = 2:(¼+²/₄)⁻¹ = 2:(3/4)⁻¹ =

= 2:(4/3)  = 2·3/4 = 3/2 = 1½