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a=4
b=3
c=√4²+3²=√25=5
r =½c=2,5
pole koła=πr²=π×2,5²=6,25πj.²
zad.2
(n-2)×180=140n
180n-140n=360
40n=360
n=360:40
n=9=ilosc boków
zad.3
a=6cm
h=6√3:2=3√3=r okregu
obwód koła=2πr=2×π×3√3=6√3πcm
zad.4
a=9
h=9√3:2
h=4,5√3
⅔h=3√3
pole koła=πr²=π×(3√3)²=27πj.²