2(
a) 2(√10-√15)²-3(√15+√10)²-(3√15-√10)(3√15+√10)=
=2(10-2√150+15)-3(15+2√150+10)-(9·15-10)=
=2(25-10√6)-3(25+10√6)-125=50-20√6-75-30√6-125=-150-50√3
b) (√20+√45)²-(2√20-√45)²-2(√45-3√20)²=
=20+2√900+45-(80-4√900-45)-2(45-6√900+180)=
=65+60-(35-120)-2(225-180)=125-35+120-2·45=210-90=120
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a) 2(√10-√15)²-3(√15+√10)²-(3√15-√10)(3√15+√10)=
=2(10-2√150+15)-3(15+2√150+10)-(9·15-10)=
=2(25-10√6)-3(25+10√6)-125=50-20√6-75-30√6-125=-150-50√3
b) (√20+√45)²-(2√20-√45)²-2(√45-3√20)²=
=20+2√900+45-(80-4√900-45)-2(45-6√900+180)=
=65+60-(35-120)-2(225-180)=125-35+120-2·45=210-90=120