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Loga x = y ---------> x = a^y
log2(x)=-1/2 --------> x = 2^(-1/2)
x = 1/2^(1/2)
x = 1/√2
Tienes log2(x) = -1/2 entonces al pasarlo a forma exponencial es 2^(-1/2)
x = 2^(-1/2)