Oblicz 1/2 tg x +2 sin x jeśli:
sin( x+ pi) = - pierwiastek z 3/2 i 0 < x <pi/2
sin ( x + pi) = - sin x = - p(3)/2
zatem
sin x = p(3)/2
x = pi/3 ( 60 stopni)
tg ( pi/3) = p(3)
czyli
(1/2) tg x + 2 sin x = (1/2)* p(3) + 2*[ p(3)/2] = (1/2) p(3) + p(3) = (3/2) p(3)
Odp. (3/2) p(3)
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p(3) <-- pierwiastek kwadratowy z 3
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sin ( x + pi) = - sin x = - p(3)/2
zatem
sin x = p(3)/2
x = pi/3 ( 60 stopni)
tg ( pi/3) = p(3)
czyli
(1/2) tg x + 2 sin x = (1/2)* p(3) + 2*[ p(3)/2] = (1/2) p(3) + p(3) = (3/2) p(3)
Odp. (3/2) p(3)
===============
p(3) <-- pierwiastek kwadratowy z 3
-------------------------------------------------