" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
permasalahan deret geometri
dik :
a = 2
r = 3/2
Dit : jumlah 6 suku pertama
jawab :
Sn untuk geometri dapat dicari menggunakan rumus
Sn = a (r^n - 1)/(r-1)
Sn = 2 ((3/2)^6 -1) / (6-1)
Sn = (2/5) (( 3^6 / 2^ 6) - 1)
Sn = silahkan cari sendiri selesaian pastinya
mudah2an membantu..
The-L
r = 3/2
S6 = [a( r^6 - 1)] / (r - 1)
s6 = [2 ( 729 / 64 - 64 /64)] / (3/2 - 1)
S6 = [2 (665/64] / 1/2
s6 = 4 (665 / 64)
S6 = 665 /16