20. Wiadomo, że liczby p i q są dodatnie i q < 6 oraz p+2q = 4.
8+p
Wykaż, że log√₂ ------- = 2
6-q
log√₂ =2
x=2
8+p / 6-q =2
8+p=12-2q
p=12-2q-8
p=4-2q
podstawiam za p
8+4-2q/6-q = 2
12-2q/6-q =2
2(6-q) /6-q=2
2=2
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log√₂ =2
x=2
8+p / 6-q =2
8+p=12-2q
p=12-2q-8
p=4-2q
podstawiam za p
8+4-2q/6-q = 2
12-2q/6-q =2
2(6-q) /6-q=2
2=2