Question

Tolong ya no 19/20 makasih banyak

Answer 1

Verified answer

19.keliling alas kerucut=2 Vi r =2×22/7 r=66
r=66×7/22:2=21/2=10,5
volume kerucut
=1/3 Vi r^2×t
=1/3×22/7×10,5×10,5×30=3465cm3
20.s=10
luas selimut +luas alas=188,4+113,04=301,44 cm2

Answer 2

19. rumus : phi x r x r x t

22/7 x (66 = 2 x 22/7 x r x r # r^2 =66/6.28 = 10.5095541 )x 30

22/7 x 10.5095541 x 10.5095541 x 30 = 10385.55

20.rumus : phi x r x r + phi x r x s

22/7 x 6 x 6 + 22/7 x 6 x (6^2 + 8^ 2 = 36 + 64 = √100 = 10 )

113.04 + 188.4 = 301.44

maaf kalau salah