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0,5· 4√8= 2√8
tw. pitagorasa
(2√6)² + (2√3)²= x²
x²= 24 + 12
x²= 36
x= 6
a√2= 4√6
Pp= (4√3)²= 48 cm²
(2√3)² + (2√3)²= h²
h²= 12 + 12
h²= 24
h= √24= 2√6
Pb=
Pc= (48 + 48√2) cm²
V= · 48· 2√3= 16· 2√3= 32√3 cm³
+ załącznik 1
14)
h= 6
12² + 2²= x²
x²= 144 + 4
x²= 148
x= √148= 2√37
Pb=
Pc= (12√3 + 12√111) dm²
+ załącznik 2