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Saya coba bantu yah !Penyelesaian :
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Diket : f (2x + 1) = 6x + 2 , g (x/2) = -x + 5
Pertama , kita ubah dulu fungsi f (2x + 1) dan g (x/2) menjadi bentuk fungsi f (x) dan g (x) :
Mengubah menjadi fungsi f (x) :
f (2x + 1) = 6x + 2
Misalkan :
y = 2x + 1
2x = y - 1
x = (y - 1) / 2
f (2x + 2) = 6x + 2
f (y) = 6 ((y - 1) / 2) + 2
f (y) = 3 (y - 1) + 2
f (y) = 3y - 3 + 2
f (x) = 3x - 1
Mengubah menjadi fungsi g (x) :
g (x/2) = -x + 5
Misalkan :
y = x/2
x = 2y
g (x/2) = -x + 5
g (y) = -2y + 5
g (x) = -2x + 5
Maka,
(f - g) (x) = f (x) - g (x)
(f - g) (x) = (3x - 1) - (-2x + 5)
(f - g) (x) = 3x - 1 + 2x - 5
(f - g) (x) = 3x + 2x - 1 - 5
(f - g) (x) = 5x - 6
Jadi, (f - g) (x) adalah 5x - 6
Semoga bisa membantu yah