Pada segitiga ABC, besar sudut A=1/2 sudut C, dan sudut B= 1 1/2 sudut A. hitunglah besar sudut-sudut segitiga ABC tersebut!
kikiarstwt
A = 1/2 C B = 1 1/2 A = 3/2 x 1/2 C = 3/4 C A+B+C = 180° 1/2 C + 3/4 C + C = 180° 2/4 C + 3/4 C + 4/4 C = 180° 9/4 C = 180° 9C = 720° C = 80°
B = 1 1/2 A
= 3/2 x 1/2 C
= 3/4 C
A+B+C = 180°
1/2 C + 3/4 C + C = 180°
2/4 C + 3/4 C + 4/4 C = 180°
9/4 C = 180°
9C = 720°
C = 80°
mk A = 1/2 x 80° = 40°
B = 3/4 x 80 = 60°