bartia1994
2 x ³+ 3=x ²+6x 2 x ³-x ²-6x+3=0 x ²(2x-1)-3(2x-1)=0 (2x-1)*(x ²-3)=0 =>(x ²-3) = 0 i (2x-1) = 0 =>x ² = 3 i 2x = 1 =>x = √3 v x = -√3 i x =½
(=> - wynika z tego że:) (v -lub)
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Asiula28
2 x ³ + 3 = x ² + 6x 2 x ³ + 3 -x ² - 6x = 0 2 x ³ -x ² - 6x+ 3 = 0 x ² ( 2x -1) - 3(2x-1) =0 (x ²-3)(2x-1)=0 (x ²-3) = 0 i (2x-1) = 0 x ² = 3 i 2x = 1 x = √3 lub x = -√3 i x =½
2 x ³-x ²-6x+3=0
x ²(2x-1)-3(2x-1)=0
(2x-1)*(x ²-3)=0
=>(x ²-3) = 0 i (2x-1) = 0
=>x ² = 3 i 2x = 1
=>x = √3 v x = -√3 i x =½
(=> - wynika z tego że:)
(v -lub)
2 x ³ + 3 -x ² - 6x = 0
2 x ³ -x ² - 6x+ 3 = 0
x ² ( 2x -1) - 3(2x-1) =0
(x ²-3)(2x-1)=0
(x ²-3) = 0 i (2x-1) = 0
x ² = 3 i 2x = 1
x = √3 lub x = -√3 i x =½