2 równania do rozwiązania.... Question from @KSB1951

KSB1951 @KSB1951

January 2019 2 20 Report

2 równania do rozwiązania
$( \sqrt{5}-1)( \sqrt{5}+1)-(5x+1)^{2}+(3x-2) ^{2}=-16 x^{2}$
$(x+3^{102}) ^{2} -(x-3 ^{102}) ^{2}=4(3 ^{102})$

wik8947201 Odp. w zalaczniku.
.................................

0 votes Thanks 0

basetla $(\sqrt{5x}-1)(\sqrt{5x}+1)-(5x+1)^{2}+(3x-2)^{2}+ = -16x^{2}\\\\5x-1-(25x^{2}+10x+1)+9x^{2}-12x+4+16x^{2} = 0\\\\5x-1-25x^{2}-10x-1+9x^{2}-12x+4+16x^{2} = 0\\\\-25x^{2}+9x^{2}+16x^{2}+5x-10x-12x-1-1+4 = 0\\\\-17x+2 = 0\\\\-17x = -2 \ \ \ \ /:(-17)\\\\x = \frac{2}{17}$

$(x+3^{102})^{2}-(x-3^{102})^{2} = 4(3^{102})$

$(x+3^{102}-x+3^{102})(x+3^{102}+x-3^{102}) = 4*3^{102}$

$2*3^{102}*2x = 4*3^{102 \ \ \ \ |:2*3^{102}$

$2x = 2$

$x = 1$

0 votes Thanks 0

About Us

Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

( \sqrt{5}x -1) ( \sqrt{5} x+1) - ( 5x+1) ^{2} +(3x-2) ^{2}=-16 x^{2}

Notacja wykładnicza, pytanie w załączniku, daje naj ;)

Recommend Questions

Life Enjoy

Get in touch

Social