Question

Diketahui f'(x) = sin^2 1/2x - cos^2 1/2x dan f(1/2 pi) = 3, tentukanlah fungsi f(x) !

Pi = 180 derajat!!!

Bantuin yaa.. Pr nihh..

Answer 1

F '(x) = sin² 1/2 x  - cos² 1/2 x = - (cos² 1/2 x  - sin² 1/2 x)
f ' (x) = - cos 2(1/2x) = - cos x
F(x) = ∫f'(x) = - sin x + c
F(π/2) = 3 --> - sin π/2 + c = 3
0 +c = 3--> c = 3
F(x)= -sin x + 3