Jawab:
diagonal ruang kubus = 9√3 cm
rumus diagonal ruang kubus= s√3
a. jadi s=9 cm
b. panjang kawat=
ada 12 rusuk, jadi 9 x 12= 108 cm
c. Luas permukaan= 6 x s x s= 6 x 9 x 9= 486 cm^2
a). panjang rusuk kubus
[tex] \frac{d}{ \sqrt{3} } = \frac{9 \sqrt{3} \: cm}{ \sqrt{3} } = 9 \: cm \\ \\ b).panjang \: kawat \\ 12 \times panjang \: rusuk \\ 12 \times 9 \: cm = 108 \: cm \\ \\ c).luas \: permukaan \: kubus \\ 6 \times rusuk \times rusuk \\ 6 \times 9 \: cm \times 9 \: cm \\ 486 \: {cm}^{2} [/tex]
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Jawab:
diagonal ruang kubus = 9√3 cm
rumus diagonal ruang kubus= s√3
a. jadi s=9 cm
b. panjang kawat=
ada 12 rusuk, jadi 9 x 12= 108 cm
c. Luas permukaan= 6 x s x s= 6 x 9 x 9= 486 cm^2
Verified answer
a). panjang rusuk kubus
[tex] \frac{d}{ \sqrt{3} } = \frac{9 \sqrt{3} \: cm}{ \sqrt{3} } = 9 \: cm \\ \\ b).panjang \: kawat \\ 12 \times panjang \: rusuk \\ 12 \times 9 \: cm = 108 \: cm \\ \\ c).luas \: permukaan \: kubus \\ 6 \times rusuk \times rusuk \\ 6 \times 9 \: cm \times 9 \: cm \\ 486 \: {cm}^{2} [/tex]