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sinx - cosx = 0,5 /²
sin^2x + cos²x - 2sinxcox = 0,25
Wiemy, że:
sin^2x + cos²x = 1
Więc:
1 - 2sinxcosx = 0,25
0,75 = 2sinxcosx
3/8 = sinxcosx
b)
Z wzoru skróconego mnożenia:
sin³x-cos³x=(sinx-cox)(sin²x+sinxcosx+cos²x) =
0,5(1 + 3/8) = 11/16