Question

{2^(p+2)+2^(p+4)+2(p+6)}/128 = 21/2 maka nilai p^2+4 adalah

Answer 1

[2^p.4+2^p.16+2^p.64]/2^7=21/2
2^p.2^2(1+4+16)/2^7=21/2
2^p.2^2.21/2^7=21/2
2^(p+3)=2^7
p+3=7
p=4
maka p^2+4=4^2+4=20