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Verified answer
Saya coba bantu yah !Penyelesaian :
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x² - (2a + 3)x + 3a = 0
Maka ,
a = 1
b = - (2a + 3) = -2a - 3
c = 3a
Harus diingat --> Syarat akar akar berkebalikan adalah c = a
c = a
3a = 1
a = 1/3
Jadi, jawabannya bkn B. -3/2, tapi jawaban yang benar adalah D. 1/3
Semoga bisa membantu
Verified answer
X^2 - (2a + 3)x + 3a = 0Jika akar-akarnya berkebalikan : x1 = 1/x2
x1 . x2 = c/a
1/x2 . x2 = 3a/1
1 = 3a
a = 1/3
Jika akar-akarnya berlawanan : x1 = -x2
x1 + x2 = -b/a
-x2 + x2 = (2a + 3)/1
0 = 2a + 3
-2a = 3
a = -3/2