Zad10.
Wartosc liczbowom wyrazenia 2b^3-(4b^2-1)*2 dla b=-1/2 jest ruwna.
zad11.Komputer przed podwyrzkom kosztowal 8000zl,a po podwyrzce xzl.O ile procent podwyrzono cene komputera?
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zad.10
b=-½
2b³-(4b²-1)*2
2*(-½)³-(4*(-½)²-1)*2 = 2* (-¹/₈)- (4*¼-1)*2 = -²/₈ - (1-1)*2= -¼
zad.11
8000zł-100%
x zł- y%
y% * 8000 / 100%* x
y%= x*100% / 8000
y%= 1x/80
y%= x/80