Zapisz bez używania symbolu wartości bezwzględnej: a) I 5 - 3 √3 I ∙ I 5 + 3 √3 I b) I 2,5 + 1 7/8 I + I 15/8 - 5/2 I
a)
I 5 - 3 p(3) I - I 5 + 3 p(3) I = - 5 + 3 p(3) - 5 - 3 p(3) = - 10
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b)
I 2,5 + 1 7/8 I + I 15/8 - 5/2 I = 2,5 + 1 7/8 - 15/8 + 5/2 = 2,5 + 1 7/8 - 1 7/8 +2,5=
= 5
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3 p(3) = około 3*1,73 > 5
zatem 5 - 3 p(3) < 0 więc I 5 - 3 p(3) I = - ( 5 - 3 p(3)) = - 5 + 3 p(3)
5 + 3 p(3) > 0 więc I 5 + 3 p(3) I = 5 + 3 p(3)
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15/8 < 2 , a 5/2 > 2 zatem 15/8 - 5/2 < 0 , więc I 15/8 - 5/2 I = - ( 15/8 - 5/2) =
= - 15/8 + 5/2
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a)
I 5 - 3 p(3) I - I 5 + 3 p(3) I = - 5 + 3 p(3) - 5 - 3 p(3) = - 10
====================================================
b)
I 2,5 + 1 7/8 I + I 15/8 - 5/2 I = 2,5 + 1 7/8 - 15/8 + 5/2 = 2,5 + 1 7/8 - 1 7/8 +2,5=
= 5
==========
3 p(3) = około 3*1,73 > 5
zatem 5 - 3 p(3) < 0 więc I 5 - 3 p(3) I = - ( 5 - 3 p(3)) = - 5 + 3 p(3)
5 + 3 p(3) > 0 więc I 5 + 3 p(3) I = 5 + 3 p(3)
------------------------------------------------------
15/8 < 2 , a 5/2 > 2 zatem 15/8 - 5/2 < 0 , więc I 15/8 - 5/2 I = - ( 15/8 - 5/2) =
= - 15/8 + 5/2