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R = ¹/₂F
cos α = ..........?
Penyelesaian :
R = √(F₁² + F₂² - 2 . F₁ . F₂ . cos α)
¹/₂F = √(F² + F² - 2 . F . F . cos α)
¹/₂F = √(2F² - 2F² . cos α)
¹/₄F² = 2F² - 2F² . cos α
2F² . cos α = 2F² - ¹/₄F²
2F² . cos α = ⁷/₄F²
cos α = ⁷/₄F² / 2F²
cos α = ⁷/₄ / 2
cos α = ⁷/₄ / 2
cos α = ⁷/₈
Jadi, nilai dari cos α adalah ⁷/₈