Question

oblicz plis tylko jedno zad.

(-2)do pot.3 [(-2/3)*(2/3 w tym że 2 jest do pot 3 a 3 do pot.2)do pot 1-2/3 a3 do pot 2 * ( -3/2 a 2 do pot 3 jest

(1 i 1/4)* (1/2) do pot 1 wiem że trudne jak by co to zbiór zadań str.16 zad25 c)

Answer 1

(-2)³[(-2/3)* 2³/3²)⁻¹ - 2/3² *(-3/2³)  =

 = -8 * [ (-2/3) * 8/9)⁻¹  - 2/9 * (-3/8) =

= -8 * [-16/27)⁻¹ - 1/12  = 

= -8 * (-27/16) - 1/12 =

 = 27/2 - 1/12 =

 = 162/12 - 1/12 =

 = 161/12=

= 13  5/12

 

 

(1  1/4)  * (1/2)¹ = 5/4  * 1/2 = 5/8